0=-10+1.35s^2

Solution for 0=-10+1.35s^2 equation:

0=-10+1.35s^2

We move all terms to the left:

0-(-10+1.35s^2)=0

We add all the numbers together, and all the variables

-(-10+1.35s^2)=0

We get rid of parentheses

-1.35s^2+10=0

a = -1.35; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-1.35)·10
Δ = 54
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{54}=\sqrt{9*6}=\sqrt{9}*\sqrt{6}=3\sqrt{6}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{6}}{2*-1.35}=\frac{0-3\sqrt{6}}{-2.7}
=-\frac{3\sqrt{6}}{-2.7}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{6}}{2*-1.35}=\frac{0+3\sqrt{6}}{-2.7}
=\frac{3\sqrt{6}}{-2.7}
$